[Haskell] readList oddity
Johannes Waldmann
waldmann at imn.htwk-leipzig.de
Thu Oct 21 03:55:08 EDT 2004
recently I was surprised by readList's behaviour (I'm no implying it is
wrong). Look at this:
data R = R deriving Show
instance Read R where
readsPrec p cs = do
( x, cs' ) <- lex cs
case x of "R" -> return (R, cs')
_ -> error "no R"
that is, we have a "very eager" parser: if it does not accept the token,
it will raise an exception. now - which of the following will work?
check0 :: [R]
check0 = read "[ ]"
check1 :: [R]
check1 = read "[ R ]"
check2 :: [R]
check2 = read "[ R, R ]"
turns out that check1 and check2 work, but check0 will not (I thought it
would). The implementation (in the Prelude) seems to think that "]" (in
check0) could possibly be the beginning of a list element.
--
-- Johannes Waldmann, Tel/Fax: (0341) 3076 6479 / 6480 --
------ http://www.imn.htwk-leipzig.de/~waldmann/ ---------
More information about the Haskell
mailing list