[Haskell-cafe] Re: problems with square roots...

[Scherrer, Chad]

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From: Daniel Carrera <daniel.carrera at zmsl.com>


Hey,

The sqrt function is not doing what I want. This is what I want:

round sqrt(2)
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Daniel,

A lot of Haskell folks like to avoid parentheses as much as possible, and there's a really
convenient way to do this. There is a Prelude function
($) f x = f x
which is right-associative, so you can write
round $ sqrt x == round (sqrt x)
This becomes really convenient when multiple application is involved:
print $ round $ sqrt x == print (round (sqrt x))

-Chad