[Haskell-cafe] Re: problems with square roots...

[Creighton Hogg]

On Wed, 21 Dec 2005, Scherrer, Chad wrote:

> ------------
> From: Daniel Carrera <daniel.carrera at zmsl.com>
> 
> 
> Hey,
> 
> The sqrt function is not doing what I want. This is what I want:
> 
> round sqrt(2)
> ---------------------------------------------------
> Daniel,
> 
> A lot of Haskell folks like to avoid parentheses as much as possible, and there's a really
> convenient way to do this. There is a Prelude function
> ($) f x = f x
> which is right-associative, so you can write
> round $ sqrt x == round (sqrt x)
> This becomes really convenient when multiple application is involved:
> print $ round $ sqrt x == print (round (sqrt x))

Doesn't it sometimes feel like the $ operator is Haskell's 
way of saying "We're not with those Lisp guys, seriously"?