Equality constraint type mismatch

[C Rodrigues]

I see.  The type inference algorithm requires type variables to betype constructors, not functions.  Equality constraints aresimplified assuming that is the case.  I knew that typefunctions had to be fully applied, but I didn't know that they alsocouldn't be "taken apart" by unification.  This explains why thefollowing doesn't typecheck:type family T a :: *my_id :: f a -> f a; my_id = idx :: T a -> T a; x = my_idIMHO, this was not clear from the documentation or from the errormessage (It certainly _looks_ like "T a" should match "f a"...).Thanks for the explanation.-heatsink 		 	   		  
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