[Haskell-beginners] Do IO actions *have* to be glued by the do syntax?

[Sumit Sahrawat, Maths & Computing, IIT (BHU)]

Sorry, autocorrect changed learnhaskell to something else.
On 22-Mar-2016 5:16 pm, "Sumit Sahrawat, Maths & Computing, IIT (BHU)" <
sumit.sahrawat.apm13 at iitbhu.ac.in> wrote:

> Olumide, do blocks are indeed syntactic sugar. They are a piece of syntax
> that converts to a specific type of expressions, namely those using the
> bind (>>=) operator.
>
> It is really helpful, when learning to be able to come up with answers in
> your own. Learning Haskell has always involved combining many different
> perspectives on the same topic, told differently in different places. It
> would only help you if you took the time and dug further for answers. It's
> really satisfying too!
>
> Also, if you haven't, search for the Leavenworth guide. It takes this very
> question in one of the miscellaneous discussions.
>
> Be nice, be respectful. Have fun learning Haskell :)
> On 22-Mar-2016 5:07 pm, "Olumide" <50295 at web.de> wrote:
>
>> Quanyang,
>>
>> do bocks are *not* sugar, and please refer to Daniel's answer for an
>> example of how to answer a beginner's question.
>>
>> - Olumide
>>
>> On 22/03/2016 11:06, Quanyang Liu wrote:
>>
>>> On Tue, Mar 22 2016 at 18:52:41 +0800, Olumide wrote:
>>>
>>>> Hello List,
>>>>
>>>> Do IO actions *have* to be glued by the do syntax? Many, if not all,
>>>> the examples that I've come across in LYH seem to suggest so. And if
>>>> so, why?
>>>>
>>>> BTW, if possible I'd appreciate an explanation that does not resort to
>>>> monads. I haven't studied them yet and I'm sure I'd struggle to
>>>> understand any explanation that resorts to monads.
>>>>
>>>>
>>> I think you should google that first... do blocks are just sugar...
>>>
>>> Thanks,
>>>>
>>>> - Olumide
>>>>
>>>
>>>
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