[Haskell-beginners] Re: Offside rule for function arguments?

[John Smith]

The indentation on the second line would generate a parse error, the same as it does now.

On 23/08/2010 12:32, Jonas Almström Duregård wrote:
> Maybe because of this:
>
> function 0 = 0 where
>   fun     1 = 1
>           2 = 2
>
> The last declaration (2=2) can define either fun or function. I'm not saying this is a major problem, but there may be
> other problems like these.
>
> /J
>
> On 23 August 2010 11:15, Brent Yorgey <byorgey at seas.upenn.edu <mailto:byorgey at seas.upenn.edu>> wrote:
>  > On Mon, Aug 23, 2010 at 09:33:13AM +0300, John Smith wrote:
>  >> Why doesn't Haskell allow something like this?
>  >>
>  >> fac 0 = 0
>  >>     1 = 1
>  >>     x = x * fac (x-1)
>  >>
>  >> This would be clearer than repeating the function name each time,
>  >> and follow the same pattern as guards and case.
>  >
>  > Good question.  I don't know of any particular reason.
>  >
>  > -Brent