[Haskell-beginners] Offside rule for function arguments?

Mon Aug 23 05:32:45 EDT 2010

Maybe because of this:

function 0 = 0 where
 fun     1 = 1
         2 = 2

The last declaration (2=2) can define either fun or function. I'm not saying
this is a major problem, but there may be other problems like these.

/J

On 23 August 2010 11:15, Brent Yorgey <byorgey at seas.upenn.edu> wrote:
> On Mon, Aug 23, 2010 at 09:33:13AM +0300, John Smith wrote:
>> Why doesn't Haskell allow something like this?
>>
>> fac 0 = 0
>>     1 = 1
>>     x = x * fac (x-1)
>>
>> This would be clearer than repeating the function name each time,
>> and follow the same pattern as guards and case.
>
> Good question.  I don't know of any particular reason.
>
> -Brent
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