[Haskell-beginners] Re: Offside rule for function arguments?

[Jonas Almström Duregård]

> The indentation on the second line would generate a parse error, the same
as it does now.
What parser error is that? Both

function 0 = 0 where
 fun     1 = 1
function 2 = 2

and

function 0 = 0 where
 fun     1 = 1
 fun     2 = 2

works for me.

/J

On 23 August 2010 11:46, John Smith <voldermort at hotmail.com> wrote:

> The indentation on the second line would generate a parse error, the same
> as it does now.
>
>
> On 23/08/2010 12:32, Jonas Almström Duregård wrote:
>
>> Maybe because of this:
>>
>> function 0 = 0 where
>>  fun     1 = 1
>>          2 = 2
>>
>> The last declaration (2=2) can define either fun or function. I'm not
>> saying this is a major problem, but there may be
>> other problems like these.
>>
>> /J
>>
>> On 23 August 2010 11:15, Brent Yorgey <byorgey at seas.upenn.edu <mailto:
>> byorgey at seas.upenn.edu>> wrote:
>>  > On Mon, Aug 23, 2010 at 09:33:13AM +0300, John Smith wrote:
>>  >> Why doesn't Haskell allow something like this?
>>  >>
>>  >> fac 0 = 0
>>  >>     1 = 1
>>  >>     x = x * fac (x-1)
>>  >>
>>  >> This would be clearer than repeating the function name each time,
>>  >> and follow the same pattern as guards and case.
>>  >
>>  > Good question.  I don't know of any particular reason.
>>  >
>>  > -Brent
>>
>
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