Is a a way to do a “Bare” state monad in modern Haskell?

Carter Schonwald carter.schonwald at
Sat Feb 22 20:45:52 UTC 2020

1) we have a monad instance for (r -> )

2) is there some way we can arrange sans newtype an instance for its state
monad sibling ( /\ x . s-> (s,x)) without a type lambda or some new type or
injective type families?  I can definitely see that this is def not
possible with h98-h2010, is this otherwise expressible?

Mostly just curious if there’s some trick that’s now possible :)
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