Seeking comments on proposed fusion rules
David Feuer
david.feuer at gmail.com
Fri Aug 15 03:33:14 UTC 2014
So you're saying you don't think the apparent cons-duplication resulting
from cons/build is really a problem? If so, that's a relief, because I
didn't have much luck getting my more complex scheme to work properly.
On Aug 14, 2014 11:28 PM, "wren romano" <winterkoninkje at gmail.com> wrote:
> On Thu, Jul 31, 2014 at 3:33 PM, David Feuer <david.feuer at gmail.com>
> wrote:
> > -- The foldr/cons rule looks nice, but it can give disastrously
> > -- bloated code when commpiling
> > -- array (a,b) [(1,2), (2,2), (3,2), ...very long list... ]
> > -- i.e. when there are very very long literal lists
> > -- So I've disabled it for now. We could have special cases
> > -- for short lists, I suppose.
> > -- "foldr/cons" forall k z x xs. foldr k z (x:xs) = k x (foldr k z xs)
>
> Yes, the foldr/cons rule is a bad idea. However, the cons/build rule
> should be fine.
>
> Both rules have the goal of reducing foldr/cons/build. The problem
> shows up when we don't have that full pattern. The failure mode of
> foldr/cons is ridiculously bloated code when the list doesn't end in a
> build. I can't really think of a failure mode for cons/build.
>
> When there's no foldr to cancel with, the build will be inlined; thus,
> the original (x : build g) which became build(\c n -> c x (g c n))
> will then become (x : g (:) []) in the end. If we did not have the
> cons/build rule, then inlining of build would transform the original
> (x : build g) into (x : g (:) []) directly. So having the rule, or
> not, doesn't change the end result. In both cases we might complain
> that g(:)[] is too slow, but then in both cases we'd expect there to
> be a g-specific rule for rewriting g(:)[] into some g'.
>
> The other possibility for a failure mode would be when there *is* a
> foldr to cancel with but the cons function is really large— since the
> cons/build rule duplicates the use of the cons function. That is, we
> may worry about code like (foldr c0 n0 (x1:x2....:xN : build g)) where
> N is large. However, note that after applying cons/build repeatedly
> and then applying foldr/build, we end up with the code ((\c n -> c x1
> (c x2 (... (c xN (g c n))...))) c0 n0) —that is, the rules produce a
> beta-redex, they do not perform the substitution themselves. Since
> beta-reduction is not performed by rewrite rules, the beta-reducer
> already has to handle the issue of duplication.
>
> --
> Live well,
> ~wren
>
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://www.haskell.org/pipermail/libraries/attachments/20140814/030fa2e7/attachment.html>
More information about the Libraries
mailing list