[Haskell-cafe] New type of ($) operator in GHC 8.0 is problematic
Will Yager
will.yager at gmail.com
Fri Feb 5 19:20:25 UTC 2016
Why must ($) be kind-polymorphic? It seems as though there is a small enough base of unboxed code that having e.g. ($#) would be fine.
If that won't work, would it be possible to have something like
($) :: forall k a (b :: k) . (a -> b) -> a -> b
I don't know if this is possible in Haskell now, but I believe the currently popular dependently typed languages allow this sort of thing.
>>
>> > ($) :: forall (r :: RuntimeRep) (a :: *) (b :: TYPE r). (a -> b) -> a -> b
>>
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