[Haskell-cafe] Proposal: (.:) operator in base.

[Ben]

At the semantic level of "does my program compute correct results" they're identical. At the operational level of "how fast does my program run" they're different.


On August 23, 2016 5:09:19 PM GMT+10:00, Tom Ellis <tom-lists-haskell-cafe-2013 at jaguarpaw.co.uk> wrote:
>On Mon, Aug 22, 2016 at 10:23:07PM -0700, wren romano wrote:
>>     (.) f g = \x -> f (g x)
>> 
>> vs:
>> 
>>     (.) f g x = f (g x)
>> 
>> has ramifications, though it's fairly easy to guess which one of
>those
>> two will be most performant.
>
>Are these not synonyms?  What is the meaning of
>
>    fargs var = expr
>
>if not
>
>    fargs = \var -> expr
>
>?
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-- 
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