[Haskell-cafe] Proposal: (.:) operator in base.

Ben hyarion at iinet.net.au
Tue Aug 23 07:19:38 UTC 2016

At the semantic level of "does my program compute correct results" they're identical. At the operational level of "how fast does my program run" they're different.

On August 23, 2016 5:09:19 PM GMT+10:00, Tom Ellis <tom-lists-haskell-cafe-2013 at jaguarpaw.co.uk> wrote:
>On Mon, Aug 22, 2016 at 10:23:07PM -0700, wren romano wrote:
>>     (.) f g = \x -> f (g x)
>> vs:
>>     (.) f g x = f (g x)
>> has ramifications, though it's fairly easy to guess which one of
>> two will be most performant.
>Are these not synonyms?  What is the meaning of
>    fargs var = expr
>if not
>    fargs = \var -> expr
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Sent from my Android device with K-9 Mail. Please excuse my brevity.
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