[Haskell-cafe] Monad fold

[Lyndon Maydwell]

You could do:

runKleisli . mconcat . map Kleisli :: Monoid (Kleisli m a b) => [a -> m b]
-> a -> m b

Would that work for you?


On Tue, Apr 16, 2013 at 8:35 PM, Christopher Howard <
christopher.howard at frigidcode.com> wrote:

> So, I'm doing something like this
>
> foldl (>>=) someA list :: Monad m => m a
>
> where
>   list :: Monad m => [a -> m a],
>   someA :: Monad m => m a
>
> Is there a more concise way to write this? I don't think foldM is what I
> want -- or is it?
>
> --
> frigidcode.com
>
>
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