[Haskell-cafe] Monad fold

Christopher Howard christopher.howard at frigidcode.com
Tue Apr 16 14:35:39 CEST 2013

So, I'm doing something like this

foldl (>>=) someA list :: Monad m => m a

  list :: Monad m => [a -> m a],
  someA :: Monad m => m a

Is there a more concise way to write this? I don't think foldM is what I
want -- or is it?


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