[Haskell-cafe] what is the purpose of GHC.Exts.lazy?

[jared simpson]

docs say:

The call '(lazy e)' means the same as e, but lazy<http://hackage.haskell.org/packages/archive/base/latest/doc/html/GHC-Exts.html#v:lazy> has 
a magical strictness property: it is lazy in its first argument, even 
though its semantics is strict.
why do i want to use magic during strictness analysis?
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