[Haskell-cafe] How to get a file path to the program invoked?
Brandon Allbery
allbery.b at gmail.com
Thu Dec 1 21:20:03 CET 2011
On Thu, Dec 1, 2011 at 14:26, dokondr <dokondr at gmail.com> wrote:
> On the contrary, standard shell variable $0 - contains a full path to the
> program location in the directory structure, no matter from what directory
> the program was called
If the shell found it by $PATH search, $0 will be simply the program name
with no directory and you will have to repeat the PATH search yourself.
(And the pathological case: the user did "PATH=something yourprog", where
"something" does not contain the directory holding "yourprog".)
There is no 100% reliable way to get the executable without using something
like /proc/self/exe (only on Linux).
--
brandon s allbery allbery.b at gmail.com
wandering unix systems administrator (available) (412) 475-9364 vm/sms
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