[Haskell-cafe] How to get a file path to the program invoked?

[dokondr]

System.Directory.getCurrentDirectory does not solve the problem.
System.Directory.getCurrentDirectory returns the directory *from which* the
program was called, also called "working directory".
The directory *from which* the program was called is not the same that the
directory *where the program executable is*, which my program needs to know.
For example:
/opt/myApp/test/myProg  - is a program
One may call it in many ways:
1)
cd /opt/myApp/test/
./myProg
Current or working directory: ./

or:

2)
cd /usr/local
/opt/myApp/test/myProg
Current or working directory: /usr/local

On the contrary, standard shell variable $0 - contains a full path to the
program location in the directory structure, no matter from what directory
the program was called.

How to find this path using GHC libraries?


On Thu, Dec 1, 2011 at 8:53 PM, Felipe Almeida Lessa <felipe.lessa at gmail.com
> wrote:

>
> Neither does $0, does it?  It depends on how the program is called.
>
> You can always use System.Directory.getCurrentDirectory with
> System.FilePath.{isRelative,replaceDirectory} if you somehow need the
> full path.  Note, however, that not even this is generally guaranteed
> to be correct.
>
> Cheers,
>
> --
> Felipe.
>



-- 
All the best,
Dmitri O. Kondratiev

"This is what keeps me going: discovery"
dokondr at gmail.com
http://sites.google.com/site/dokondr/welcome
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://www.haskell.org/pipermail/haskell-cafe/attachments/20111201/b6cc67e0/attachment.htm>