[Haskell-cafe] Re: Type of (>>= f) where f :: a -> m b

Milind Patil milind_patil at hotmail.com
Mon May 10 06:45:49 EDT 2010

David Menendez <dave <at> zednenem.com> writes:
> It's because >>= is a binary operator. When you partially apply a
> binary operator, you get a "section" which applies one of the two
> arguments.

Understood :-)! Thanks for the responses -- both of them.

Milind Patil

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