[Haskell-cafe] Why is it so different between 6.12.1 and 6.10.4_1 ?

[zaxis]

I just mean syntax.  For example. the following code snippet is C-style. In
vim, i can use `shift+%` to jump between `{' and `}', and so on.   

hitSSQ hitNum = do {
    nums <- fmap str_ints_pick $ readFile "ssqNum.txt";
    forM_ nums (\n -> do {
        let { hitB = if (n!!6 == hitNum!!6) then 1 else 0 ;
            hitR = foldl (\acc x -> if(elem x (init hitNum)) then acc+1 else
acc) 0 (init n);};
        printf "%s\t%d:%d\t%s\n" (show n) (hitR::Int) (hitB::Int) (hit_desc
hitR hitB);
    });
}


Dietrich Epp-2 wrote:
> 
> I think Miljenovic was asking about this (I removed explicit braces):
> 
>      fac n = let f = foldr (*) 1 [1..n] in f
> 
> Which is strictly equivalent to:
> 
>      fac n = foldr (*) 1 [1..n]
> 
> Translated into C, this is kind of like doing this:
> 
>      int add(int x, int y)
>      {
>          int sum = x + y;
>          return sum;
>      }
> 
> instead of this:
> 
>      int add(int x, int y)
>      {
>          return x + y;
>      }
> 
> I find it very cumbersome (though not *difficult*) and painful to use  
> a C style of programming with Haskell, so I am not sure what you mean  
> when you ask why Haskell supports C style.  Are you talking about  
> mutable state, syntax, or something else?
> 
> --Dietrich
> 
> On 2010 March 27, at 4:28, zaxis wrote:
> 
>>
>> Of course, you are wrong !  C is VERY important for almost every  
>> programmer
>> in the world!  Why cannot C programmer use haskell ?   And Why does  
>> haskell
>> support C code style ?
>>
>>
>> Ivan Miljenovic wrote:
>>>
>>> zaxis <z_axis at 163.com> writes:
>>>
>>>>>> Why do you bother with the interior definition of f in there?
>>>> Because i want to try a C code style not layout style without `do`  
>>>> syntax
>>>> sugar .
>>>
>>> Haskell /= C, so stop trying to code as if it is.  If you like C so
>>> much, then use C.
>>>
>>> -- 
>>> Ivan Lazar Miljenovic
>>> Ivan.Miljenovic at gmail.com
>>> IvanMiljenovic.wordpress.com
>>> _______________________________________________
>>> Haskell-Cafe mailing list
>>> Haskell-Cafe at haskell.org
>>> http://www.haskell.org/mailman/listinfo/haskell-cafe
>>>
>>>
>>
>>
>> -----
>> fac n = let {  f = foldr (*) 1 [1..n] } in f
>> -- 
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>>
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> 
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-----
fac n = let {  f = foldr (*) 1 [1..n] } in f 
-- 
View this message in context: http://old.nabble.com/Why-is-it-so-different-between-6.12.1-and-6.10.4_1---tp28049329p28056674.html
Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.