[Haskell-cafe] Re: Laziness question
Janis Voigtländer
jv at informatik.uni-bonn.de
Mon Aug 2 11:41:02 EDT 2010
Hi,
I am late to reply in this thread, but as I see Stefan has already made
what (also from my view) are the main points:
- Putting seq in a type class makes type signatures more verbose, which
one may consider okay or not. In the past (and, as it seems, again in
every iteration of the language development process since then) the
majority of the language design decision makers have considered this
verbosity non-okay enough, so that they decided to have a fully
polymorhpic seq.
- Even if putting seq in a type class, problems with parametricity do
not simply vanish. The question is what instances there will be for that
class. (For example, if there is not instance at all, then no
seq-related problems of *any* nature can exist...)
- The Haskell 1.3 "solution" was to, among others, have a class instance
for functions. As we show in the paper Stefan mentioned, that is not a
solution. Some statements claimed by parametricity will then still be
wrong due to seq.
- If there is no class instance for function types, then those problems
go away, of course. But it is doubtful whether that would be a viable
solution. Quite a few programs would be rejected as a consequence. (Say,
you want to use the strict version of foldl. That will lead to a type
class constraint on one of the type variables. Now suppose you actually
want to fold in a higher-order fashion, like when expressing efficient
reverse via foldr. That would not anymore be possible for the strict
version of foldl, as it would require the type-class-constrained
variable to be instantiated with a function type.)
Two more specific answers to Nicolas' comments:
> Actually my point is that if we do not use any polymorphic primitive to
> implement a family of seq functions then it cannot be flawed. Indeed
> if you read type classes as a way to implicitly pass and pick > functions
> then it cannot add troubles.
Completely correct. But the point is that without using any polymorphic
primitive you won't be able to implement a member of that family for the
case of function types (which you do not consider a big restriction, but
others do).
> However I absolutely do not buy their argument using as example a function
> f :: Eval (a -> Int) => (a -> Int) -> (a -> Int) -> Int. They consider as
> an issue the fact that the type does not tell us on which argument seq is
> used. I think it is fine we may want a more precise type for it to get more
> properties out of it but it is not flawed.
> As much as we don't know where (==) is used given a function of type
> ∀ a. Eq a => [a] -> [a].
I fear you do not buy our argument since you did not fully understand
what our argument is, which in all probability is our fault in not
explaining it enough. The point is not that we dislike per se that one
doesn't know from the type signature how/where exactly methods from a
type class are used. In your example ∀ a. Eq a => [a] -> [a] it's
alright that we don't know more about where (==) is used. But for a
function of type f :: Eval (a -> Int) => (a -> Int) -> (a -> Int) ->
Int, in connection with trying to find out whether uses of seq are
harmful or not, it is absolutely *essential* to know on which of the two
functions (a -> Int) seq is used. The type class approach cannot tell
that. Hence, a type class approach is unsuitable for trying to prevent
seq from doing parametricity-damage while still allowing to write all
the Haskell programs one could before (including ones that use seq on
functions). That is the flaw of the type class approach to controlling
seq. It is of course no flaw of using type classes in Haskell for other
things, and we certainly did not meant to imply such a thing.
Best regards,
Janis.
--
Jun.-Prof. Dr. Janis Voigtländer
http://www.iai.uni-bonn.de/~jv/
mailto:jv at iai.uni-bonn.de
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