[Haskell-cafe] Re: How to decide if a number is an integer?

[Thomas DuBuisson]

Magicloud,

There are numerous ways to construct such a function.  Hoogling
"(Fractional a, Integral b) => a -> b" brings up a host of functions
that would be of use here in combination with fromIntegral.

Thomas

On Mon, Sep 28, 2009 at 11:11 PM, Magicloud Magiclouds
<magicloud.magiclouds at gmail.com> wrote:
> Hi,
>  Here is an example:
>  let l = fun num in
>  if isIntegral l
>    then l
>    else 0
>  How to do the isIntegral thing?
>
> On Tue, Sep 29, 2009 at 1:58 PM, Magicloud Magiclouds
> <magicloud.magiclouds at gmail.com> wrote:
>> Hi,
>>  In other weak-type language, `round i == i` would work. But in
>> haskell, what should I do? Thanks.
>> --
>> 竹密岂妨流水过
>> 山高哪阻野云飞
>>
>
>
>
> --
> 竹密岂妨流水过
> 山高哪阻野云飞
>
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