[Haskell-cafe] Re: How to decide if a number is an integer?

[Magicloud Magiclouds]

Hi,
  Here is an example:
  let l = fun num in
  if isIntegral l
    then l
    else 0
  How to do the isIntegral thing?

On Tue, Sep 29, 2009 at 1:58 PM, Magicloud Magiclouds
<magicloud.magiclouds at gmail.com> wrote:
> Hi,
>  In other weak-type language, `round i == i` would work. But in
> haskell, what should I do? Thanks.
> --
> 竹密岂妨流水过
> 山高哪阻野云飞
>



-- 
竹密岂妨流水过
山高哪阻野云飞