[Haskell-cafe] ghci debugger problem with :continue. is it
broken, or is it me?
florbitous at gmail.com
Sun Apr 26 10:20:13 EDT 2009
2009/4/25 Thomas Hartman <tphyahoo at gmail.com>
> In the program below, can someone explain the following debugger output to
> After :continue, shouldn't I hit the f breakpoint two more times?
> Why do I only hit the f breakpoint once?
> Is this a problem in the debugger?
> thartman at ubuntu:~/haskell-learning/debugger>cat debugger.hs
> -- try this:
> -- ghci debugger.hs
> -- > :break f
> -- > :trace t
> -- > :history -- should show you that f was called from h
> t = h . g . f $ "hey!"
> t2 = h . g . f $ "heh!"
> t3 = h . g . f $ "wey!"
> f = ("f -- " ++)
> g = ("g -- " ++)
> h = ("h -- " ++)
> ts = do
> putStrLn $ t
> putStrLn $ t2
> putStrLn $ t3
What you are observing is really an artifact of the way breakpoints are
attached to definitions in the debugger, and the way that GHCi evaluates
f is clearly a function, but its definition style is a so-called "pattern
binding". The body contains no free (lambda bound) variables, so it is also
a constant. GHCi arranges for f to be evaluated at most once. The breakpoint
associated with the definition of f is fired if and when that evaluation
takes place. Thus, in your case it fires exactly once.
You can re-write f to use a so-called "function binding" instead, by
eta-expansion (introduce a new fresh variable, and apply the function to it
on both sides):
f x = ("f -- " ++) x
This denotes the same function, but the breakpoint on f works differently.
In this case, a breakpoint attached to f will fire whenever an application
of f is reduced. If you write it this way you will see that the program
stops three times instead of one.
You might ask: if both definitions denote the same function, why does the
debugger behave differently? The short answer is that the debugger in GHCi
is an operational debugger, so it exposes some of the operational details
which may be invisible in a denotational semantics. In this case it revels
that GHCi treats the two definitions of f differently.
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