[Haskell-cafe] Re: (flawed?) benchmark : sort
ndmitchell at gmail.com
Mon Mar 10 16:34:00 EDT 2008
> But antisymmetry means that (x <= y) && (y <= x) ==> x = y, where '=' means
> identity. Now what does (should) 'identity' mean?
I think you are using the word identity when the right would would be
equality. Hence, the answer is, without a doubt, (==). If you define
equality, then you are defining equality.
> In short, I would consider code where for some x, y and a function f we have
> (x <= y) && (y <= x) [or, equivalently, compare x y == EQ] but f x /= f y
> broken indeed.
I would consider it slightly bad code too. But not broken code. I
think Ord functions can assume that Ord is a total ordering, nothing
more. Nothing to do with the existence (or otherwise) of entirely
Consider the following implementation of Data.Set, which *does* meet
all the invariants in Data.Set:
data Set a = Set [a]
insert x (Set xs) = Set $ x : filter (/= x) xs
elems (Set xs) = xs
i.e. there is real code in the base libraries which breaks this notion
of respecting classes etc. Is the interface to Data.Set broken? I
would say it isn't.
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