[Haskell-cafe] Re: 0/0 > 1 == False

[Cristian Baboi]

On Sat, 12 Jan 2008 13:23:41 +0200, Kalman Noel  
<kalman.noel at bluebottle.com> wrote:

> Achim Schneider wrote:
>> Actually, lim( 0 ) * lim( inf ) isn't anything but equals one, and
>> the anything is defined to one (or, rather, is _one_ anything) to be
>> able to use the abstraction. It's a bit like the difference between
>> eight pens and a box of pens. If someone knows how to properly
>> formalise n = 1, please speak up.
>
> Sorry if I still don't follow at all.  Here is how I understand (i. e.
> have learnt) lim notation, with n ∈ N, a_n ∈ R.  (Excuse my poor
> terminology, I have to translate this in my mind from German maths
> language ;-).  My point of posting this is that I don't see how to
> accommodate the lim notation as I know it with your term. The limit of
> infinity?  What is the limit of infinity, and why should I multiplicate
> it with 0?  Why should I get 1?
>
>     (1) lim a_n  = a                (where a ∈ R)
>     (2) lim a_n  = ∞
>     (3) lim a_n  = − ∞
>     (4) lim { x → x0 } f(x) = y     (where f is a function into R)
>
>     (1) means that the sequence of reals a_n converges towards a.
>
>     (2) means that the sequence does not converge, because you can
>         always find a value that is /larger/ than what you hoped might
>         be the limit.
>    (3) means that the sequence does not converge, because you can
>         always find a value that is /smaller/ than what you hoped might
>         be the limit.
>
>     (4) means that for any sequence of reals (x_n ∈ dom f) converging
>         towards x0, we have lim f(x_n) = y.  For this equation again, we
>         have the three cases above.

Suppose lim a_n = a , lim b_n = b, c_2n = a_n, c_2n+1 = b_n.

What is lim c_n ?


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