[Haskell-cafe] Problems interpreting

[Carajillu]

Not a good solution, it just substitutes the first occurrence of the item in
the list. I'll try the others

Carajillu wrote:
> 
> Finally I took Andrea's solution "check_elem (x:xs) = if x == e then (l2
> ++ xs) else [x] ++ check_elem xs"
> I think it's easy to understand for me ( in my noob level), than the
> recursive one. 
> I'm testing it and it's working really well. The other solutions are a
> little complicated for me, but I'm still trying to undestand them.
> Thanks!
> 
> 
> Andrea Rossato wrote:
>> 
>> On Mon, Sep 18, 2006 at 12:25:21PM +0100, Neil Mitchell wrote:
>>> Why not:
>>> > check_elem (x:xs) = if x == e then (l2 ++ xs) else x : check_elem xs
>>> 
>>> Thanks
>> 
>> Thank you! 
>> Lists are my personal nightmare...;-)
>> 
>> Andrea
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>> 
>> 
> 
> 

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