[Haskell-cafe] Problems interpreting

[Carajillu]

Finally I took Andrea's solution "check_elem (x:xs) = if x == e then (l2 ++
xs) else [x] ++ check_elem xs"
I think it's easy to understand for me ( in my noob level), than the
recursive one. 
I'm testing it and it's working really well. The other solutions are a
little complicated for me, but I'm still trying to undestand them.
Thanks!


Andrea Rossato wrote:
> 
> On Mon, Sep 18, 2006 at 12:25:21PM +0100, Neil Mitchell wrote:
>> Why not:
>> > check_elem (x:xs) = if x == e then (l2 ++ xs) else x : check_elem xs
>> 
>> Thanks
> 
> Thank you! 
> Lists are my personal nightmare...;-)
> 
> Andrea
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