[Haskell-cafe] function types as instances of Num
Simon Peyton-Jones
simonpj at microsoft.com
Wed Nov 1 04:42:43 EST 2006
Try
test' = square . (4 :: a -> (Integer,a))
Otherwise, how is the compiler to know that you want 4 to be of that
type?
S
| -----Original Message-----
| From: haskell-cafe-bounces at haskell.org
[mailto:haskell-cafe-bounces at haskell.org] On Behalf Of Greg
| Buchholz
| Sent: 26 October 2006 18:46
| To: haskell-cafe at haskell.org
| Subject: [Haskell-cafe] function types as instances of Num
|
|
| Let's say we've got a little stack language, where you compute
| things by transformations of stacks, using compositions of functions
| from stacks to stacks (represented here as nested tuples). (See also
| Chris Okasaki's "Techniques for Embedding Postfix Languages in
Haskell"
| www.eecs.harvard.edu/~nr/ cs252r/archive/chris-okasaki/hw02.ps )
|
| For example, the simple program below calculates the square of 4...
|
| > {-# OPTIONS -fglasgow-exts #-}
| >
| > main = print $ test ()
| >
| > test = square . (lit 4)
| >
| > lit :: Integer -> a -> (Integer,a)
| > lit val stack = (val, stack)
| >
| > dup (a, b) = (a, (a, b))
| > mult (a, (b, c)) = (b*a, c)
| > square = mult . dup
|
| ...now let's say I find that using the function "lit" to annotation
| numeric literals ugly. What I really want is something like...
|
| > test' = square . 4
|
| ...Seems simple enough, I'll just make an appropriate instance of Num
| and I'll be able to use fromInteger...
|
| > instance Eq (a -> (Integer, a))
| > instance Show (a -> (Integer, a))
| > instance Num (a -> (Integer, a)) where
| > fromInteger = lit
|
| ...but now when I try it, GHC complains...
|
| No instance for (Num (a -> (Integer, t)))
| arising from the literal `4' at final.hs:15:17
| Possible fix:
| add an instance declaration for (Num (a -> (Integer, t)))
| In the second argument of `(.)', namely `4'
| In the expression: square . 4
| In the definition of `test'': test' = square . 4
|
| ...so it seems that (a -> (Integer, t)) can't be unified with (a ->
| (Integer, a)), or somesuch. Any thoughts on how to get this to work?
|
|
| Thanks,
|
| Greg Buchholz
|
|
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