forall in constraint

[Alan & Kim Zimmerman]

I am working on the Trees that Grow stuff, and hit a small problem

I have

type family XIB               x thing
type family XNewImplicitBndrs x thing

type ForallXImplicitBndrs (c :: * -> Constraint) (x :: *) (thing :: *) =
       ( c (XIB               x thing)
       , c (XNewImplicitBndrs x thing)
       )

and I want to extend the DataId constraint

type DataId p =
  ( Data p

  , ForallXImplicitBndrs Data p thing
  )

But the problem is I do not have `thing` at this point, and to get it in
the code will involve some hs-boot nastiness.

Is there any way to require "forall thing. Data thing" inside the DataId
constraint?

Alan
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