Initial state of gc_thread.mut_spin
Patrick Palka
patrick
Tue Oct 1 16:11:13 UTC 2013
Hi everyone,
In new_gc_thread(), why is gc_thread.mut_spin initialized to the 'released'
state instead of the 'acquired' state (as with gc_spin)? I think this is
wrong for two reasons:
1. During the first GC (but not during subsequent GCs), gcWorkerThread()
releases mut_spin but mut_spin is not 'acquired' at this point.
2. The initial state of mut_spin is inconsistent with the final state of
mut_spin at the end of a GC (it is in the 'acquired' state then).
So it seems to me that mut_spin should be initialized to the 'acquired'
state, like gc_spin is. Doing so would address these two points.
Does this change make sense?
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://www.haskell.org/pipermail/ghc-devs/attachments/20131001/a829151d/attachment.html>
More information about the ghc-devs
mailing list