[Haskell-beginners] Monad question
Imants Cekusins
imantc at gmail.com
Thu Nov 25 18:36:02 UTC 2021
Or you could derive Traversable for Expr
Then sequenceA can be used:
https://hoogle.haskell.org/?hoogle=f%20(m%20a)%20-%3E%20m%20(f%20a)
On Thu 25 Nov 2021, 19:54 יהושע ולך, <yehoshuapw at gmail.com> wrote:
> convert (Var mx) = mx >>= (return .Var x)
>
> Should also be the non-do-notation.
> (again, typing from a phone, and not tested)
>
> On Thu, Nov 25, 2021, 19:46 יהושע ולך <yehoshuapw at gmail.com> wrote:
>
>> I can't actually cheok right now,
>> but
>> ```
>> convert (Var mv) = do
>> v <- mv
>> return $ Var v
>> ```
>>
>> is the "do notation" which should work.
>> (and similarly for the other expression)
>>
>> On Thu, Nov 25, 2021, 19:13 mike h <mike_k_houghton at yahoo.co.uk> wrote:
>>
>>> Hi,
>>> This isn’t homework! I’ve been staring at this for several hours - and
>>> that usually works.
>>> I also tried typed holes to no avail. I thinks it is quite simple
>>> really but I’ve gone past seeing it!
>>>
>>> I have
>>> data Expr a = Var a | Add (Expr a) (Expr a)
>>>
>>> and would like to write
>>>
>>> convert :: Expr (Maybe a) -> Maybe (Expr a)
>>>
>>> which returns Nothing if there is an occurrence of Nothing inside the
>>> input expression e, otherwise it returns Just e', where e'
>>> is a new expression where the internal values of type a are not wrapped
>>> in Just.
>>> You should use the functionality of the Maybe monad to implement
>>> the convert function.
>>>
>>>
>>> Thanks
>>> Mike
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