[Haskell-beginners] Monad question

[יהושע ולך]

convert (Var mx) = mx >>= (return .Var)

Typo.

On Thu, Nov 25, 2021, 19:53 יהושע ולך <yehoshuapw at gmail.com> wrote:

> convert (Var mx) = mx >>= (return .Var x)
>
> Should also be the non-do-notation.
> (again, typing from a phone, and not tested)
>
> On Thu, Nov 25, 2021, 19:46 יהושע ולך <yehoshuapw at gmail.com> wrote:
>
>> I can't actually cheok right now,
>> but
>> ```
>> convert (Var mv) = do
>>     v <- mv
>>      return $ Var v
>> ```
>>
>> is the "do notation" which should work.
>> (and similarly for the other expression)
>>
>> On Thu, Nov 25, 2021, 19:13 mike h <mike_k_houghton at yahoo.co.uk> wrote:
>>
>>> Hi,
>>> This isn’t homework! I’ve been staring at this for several hours - and
>>> that usually works.
>>> I also tried typed holes to no avail.  I thinks it is  quite simple
>>> really but I’ve gone past seeing it!
>>>
>>> I have
>>> data Expr a = Var a | Add (Expr a) (Expr a)
>>>
>>> and would like to write
>>>
>>> convert :: Expr (Maybe a) -> Maybe (Expr a)
>>>
>>> which returns Nothing if there is an occurrence of Nothing inside the
>>> input expression e, otherwise it returns Just e', where e'
>>> is a new expression where the internal values of type a are not wrapped
>>> in Just.
>>> You should use the functionality of the Maybe monad to implement
>>> the convert function.
>>>
>>>
>>> Thanks
>>> Mike
>>> _______________________________________________
>>> Beginners mailing list
>>> Beginners at haskell.org
>>> http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners
>>>
>>
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