[Haskell-beginners] foldr point free notation

[Apoorv Ingle]

Hi Alexander,

I found this tool online[1], that converts your function to a point free style.

myAny'' f = foldr (\a b -> f a || b) False

is transformed to

myAny'' = flip foldr False . ((||) .)

Again as Bob mentions, the point free style comes at a cost of unreadability and hence unmaintainable. 

Cheers!
Apoorv

[1]: http://pointfree.io/ <http://pointfree.io/>

> On Jun 10, 2020, at 10:00, Bob Ippolito <bob at redivi.com> wrote:
> 
> The better question is why would you want to? If you could even manage, the result would be practically incomprehensible. 
> 
> On Wed, Jun 10, 2020 at 07:49 Alexander Chen <alexander at chenjia.nl <mailto:alexander at chenjia.nl>> wrote:
> hi,
> 
> --any function foldr
> myAny'' :: (a-> Bool) -> [a] -> Bool
> myAny'' f = foldr (\a b -> f a || b) False
> 
> this is the foldr notions. How would i make this point free?
> 
> best,
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