[Haskell-beginners] foldr point free notation

[Bob Ippolito]

The better question is why would you want to? If you could even manage, the
result would be practically incomprehensible.

On Wed, Jun 10, 2020 at 07:49 Alexander Chen <alexander at chenjia.nl> wrote:

> hi,
>
> --any function foldr
> myAny'' :: (a-> Bool) -> [a] -> Bool
> myAny'' f = foldr (\a b -> f a || b) False
>
> this is the foldr notions. How would i make this point free?
>
> best,
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