[Haskell-beginners] Why is it so slow to solve "10^(10^10)"?

[yi lu]

I am checking whether a number equals 10^(10^10).

Yi


On Sun, Sep 22, 2013 at 7:11 AM, KC <kc1956 at gmail.com> wrote:

> Have you compared the solution to other languages?
>
> If you are only solving 10^(10^10) why not construct a string with "1"
> followed by a 100 zeroes?
>
> In other words, what is this being used for?
>
>
>
> On Sat, Sep 21, 2013 at 3:32 PM, yi lu <zhiwudazhanjiangshi at gmail.com>wrote:
>
>> Why is it so slow to solve "10^(10^10)" in Haskell?
>>
>> Yi
>>
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>
>
> --
> --
> Regards,
> KC
>
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