[Haskell-beginners] Why is it so slow to solve "10^(10^10)"?

KC kc1956 at gmail.com
Sun Sep 22 01:11:37 CEST 2013


Have you compared the solution to other languages?

If you are only solving 10^(10^10) why not construct a string with "1"
followed by a 100 zeroes?

In other words, what is this being used for?



On Sat, Sep 21, 2013 at 3:32 PM, yi lu <zhiwudazhanjiangshi at gmail.com>wrote:

> Why is it so slow to solve "10^(10^10)" in Haskell?
>
> Yi
>
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-- 
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Regards,
KC
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