[Haskell-beginners] Beginners Digest, Vol 57, Issue 15

[Patrick Lynch]

Good morning,
...anyone working with YESOD?
Good day

----- Original Message ----- 
From: <beginners-request at haskell.org>
To: <beginners at haskell.org>
Sent: Monday, March 11, 2013 7:00 AM
Subject: Beginners Digest, Vol 57, Issue 15


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> Today's Topics:
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>   1. Re:  Using stack inside a function without declaring it as
>      input (Krzysztof Skrz?tnicki)
>   2. Re:  Using stack inside a function without declaring it as
>      input (Emanuel Koczwara)
>
>
> ----------------------------------------------------------------------
>
> Message: 1
> Date: Mon, 11 Mar 2013 11:15:32 +0100
> From: Krzysztof Skrz?tnicki <gtener at gmail.com>
> Subject: Re: [Haskell-beginners] Using stack inside a function without
> declaring it as input
> To: doaltan <doaltan at yahoo.co.uk>, The Haskell-Beginners Mailing List
> - Discussion of primarily beginner-level topics related to Haskell
> <beginners at haskell.org>
> Message-ID:
> <CAM7aEVHagkBOORNwmsU-gHYm5sJixXg3hAojTDjnyA_x72tvWQ at mail.gmail.com>
> Content-Type: text/plain; charset="utf-8"
>
> There are some things clearly missing in your description. I think you 
> need
> to read your problem more carefully and perhaps consult some accompanying
> materials too.
>
> Other than that I see no way one can sensibly answer your question without
> more information.
>
> Best regards,
> Krzysztof Skrz?tnicki
>
>
> On Mon, Mar 11, 2013 at 10:36 AM, doaltan <doaltan at yahoo.co.uk> wrote:
>
>> Hi I have a function like this :
>> myfunc :: [Char] -> [Char]
>> It  is supposed to work pretty much like this :
>>
>>    1. Take a string
>>    2. Put some elements of this input string to output string and put
>>    others to stack.
>>    3. Pop elements to that output string too.
>>    4. Do 2 and 3 recursively until stack is empty.
>>    5. Print the output string when stack is empty.
>>
>>
>> I couldn't figure out where to define stack and output string. Can you
>> help me with that? I'm new to Haskell so I can't think in Haskell's logic
>> very well.
>>
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> ------------------------------
>
> Message: 2
> Date: Mon, 11 Mar 2013 11:29:27 +0100
> From: Emanuel Koczwara <poczta at emanuelkoczwara.pl>
> Subject: Re: [Haskell-beginners] Using stack inside a function without
> declaring it as input
> To: doaltan <doaltan at yahoo.co.uk>, The Haskell-Beginners Mailing List
> - Discussion of primarily beginner-level topics related to Haskell
> <beginners at haskell.org>
> Message-ID:
> <1362997767.13571.11.camel at emanuel-Dell-System-Vostro-3750>
> Content-Type: text/plain; charset="UTF-8"
>
> Hi,
>
> Dnia 2013-03-11, pon o godzinie 09:36 +0000, doaltan pisze:
>> Hi I have a function like this :
>> myfunc :: [Char] -> [Char]
>> It  is supposed to work pretty much like this :
>>      1. Take a string
>>      2. Put some elements of this input string to output string and
>>         put others to stack.
>>      3. Pop elements to that output string too.
>>      4. Do 2 and 3 recursively until stack is empty.
>>      5. Print the output string when stack is empty.
>>
>> I couldn't figure out where to define stack and output string. Can you
>> help me with that? I'm new to Haskell so I can't think in Haskell's
>> logic very well.
>>
>
>  You can try to define a second function inside myfunc with the stack
> as an argument:
>
> myfunc :: String -> String
> myfunc str = myfunc' [] str
>  where myfunc' stack str = ...
>
>  myfunc' can take the stack as an argument, myfunc can call myfunc'
> passing the empty stack.
>
>  You should describe your problem more precisely to get more accurate
> answers.
>
> Emanuel
>
>
>
>
>
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> End of Beginners Digest, Vol 57, Issue 15
> *****************************************
>