[Haskell-beginners] return IO () vs. ()
Alex Rozenshteyn
rpglover64 at gmail.com
Sat May 28 23:50:25 CEST 2011
The thing that I see as weird is (>>= return ()), since the right argument
to (>>=) is supposed to be a function.
Maybe you want (>>)
On Sat, May 28, 2011 at 5:35 PM, Neil Jensen <neilcjensen at gmail.com> wrote:
> I've been attempting to refactor some working code and running into
> confusion about returning IO values.
>
> The basic sequence is to query a database, calculate some values, and then
> store the results back in the database.
>
> The function which does the querying of the db and calculating results has
> the following type signature:
> calcCUVs :: AccountId -> IO [((ISODateInt, ISODateInt), CUV)]
>
> This function stores the results back into the database
> saveCUVs :: AccountId -> [((ISODateInt, ISODateInt), CUV)] -> IO ()
> saveCUVs account cuvs = do
> r' <- mapM (\x -> storeCUV (snd $ fst x) account (snd x)) cuvs
> return ()
>
>
> I had a working variation of the below using 'do' notation, but for some
> reason when I moved to using bind, I'm getting messed up with return values.
>
> processAccountCUVs :: AccountId -> ISODateInt -> ISODateInt -> IO ()
> processAccountCUVs account prevMonthEnd monthEnd = -- do
> if (prevMonthEnd == 0 && monthEnd == 0)
> then calcCUVs account >>= (\cuvs -> saveCUVs
> account cuvs) >>= return ()
> else calcCUVs account prevMonthEnd monthEnd >>=
> (\cuvs -> saveCUVs account cuvs) >>= return ()
>
>
> The compiler gives the following error message:
>
> Couldn't match expected type `IO ()' against inferred type `()'
> In the first argument of `return', namely `()'
> In the second argument of `(>>=)', namely `return ()'
> In the expression:
> calcCUVs account >>= (\ cuvs -> saveCUVs account cuvs) >>=
> return ()
>
>
> I thought the last return () would correctly return us IO () as we are in
> the IO monad... what am I missing?
>
> Thanks for any input you can provide.
> Neil
>
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--
Alex R
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