[Haskell-beginners] Need help understanding (1) typeclass instances that have multiple parameter types, and (2) overlapping instances
Daniel Fischer
daniel.is.fischer at googlemail.com
Sun Jun 26 17:02:04 CEST 2011
On Sunday 26 June 2011, 15:33:45, Costello, Roger L. wrote:
> Hi Folks,
>
> I have questions about:
>
> - typeclass instances that have multiple parameter types
> - overlapping instances
>
> Let's take an example of a typeclass with two instances:
>
> class MyShow a where
> toString :: a -> String
>
> instance MyShow Int where
> toString = show
>
> instance MyShow (Int, Int) where
> toString (a, b) = toString a ++ ", " ++ toString b
>
> The first instance has one parameter type (Int) and the second instance
> has two parameter types (Int, Int).
No, it also has only one parameter type, the type (Int,Int).
>
> When the class and instances are compiled, this error is generated:
>
> Illegal instance declaration for `MyShow (Int, Int)'
> (All instance types must be of the form (T a1 ... an)
> where a1 ... an are type *variables*,
> and each type variable appears at most once in the instance
> head. Use -XFlexibleInstances if you want to disable this.)
> In the instance declaration for `MyShow (Int, Int)'
>
> I interpret that error message to mean that Haskell has this rule:
>
> Instances with one parameter type can specify non-variable
> types (such as Int), but instances with multiple parameter
> types can only use variable types (e.g., a, b, c).
Int is a type constructor (of kind *), which is applied to 0 type variables
[hence the type variables it is applied to are vacuously distinct].
(Int,Int) is the type constructor (,) applied to two type arguments [which
are not type variables], both of which are the type Int.
Haskell98 (probably also Haskell2010, I'm too lazy to look it up now) says
all instance types must have the form
(type constructor) applied to distinct type variables
So
instance (MyShow a, MyShow b) => MyShow (a,b) where ...
is allowed, but none of
instance (MyShow a) => MyShow (a,a) where ... (type variables not distinct)
instance (MyShow a) => MyShow (a, Int) where .. (one non-type-variable)
instance MyShow (Int,Int) where (two non-type-variables)
instance Show a => MyShow a where ... (no type constructor)
>
> Is that the rule?
Not quite, see above.
>
> What is the rationale for that rule?
I'm not sure, I guess it's easier to implement.
>
> Next, I placed this at the top of my file:
>
> {-# LANGUAGE FlexibleInstances #-}
>
> and the error message went away.
>
> Apparently the pragma is telling the compiler:
>
> Even though the Haskell code does not strictly conform to the
> Haskell specification, please let it compile.
>
> Is that what the pragma is telling the compiler?
Yes, although in this case, it's rather "please lift an unnecessary and
cumbersome restriction on the form of instance declarations".
>
> There must be a good reason why Haskell prohibits non-variable types in
> multi-parameter instances.
Correcting the misunderstanding, it prohibits non-variable types as
arguments to type constructors in instance heads, I know of no good reason
why it does.
> So there must be a downside to adding that
> pragma. What is the downside?
Your code will only work with implementations which have the
FlexibleInstances extension.
>
>
> Now let's move on to my questions about overlapping instances.
>
> I created a third instance. It is for a pair of values of any type:
>
> instance (MyShow a, MyShow b) => MyShow (a, b) where
> toString (a, b) = ">>" ++ toString a ++ " " ++ toString b ++
> "<<"
>
> It compiles without error.
Type constructor (,) applied to two distinct type variables [a, b], that's
the form allowed by H98.
>
> But if I try to use the second instance (the one that was defined for
> two Int's):
>
> toString ((34 :: Int), (44 :: Int))
>
> then I get an overlapping instances error:
>
> Overlapping instances for MyShow (Int, Int)
> arising from a use of `toString'
> Matching instances:
> instance MyShow (Int, Int) -- Defined at Overlap.hs:11:9-25
> instance (MyShow a, MyShow b) => MyShow (a, b)
> In the expression: toString ((34 :: Int), (44 :: Int))
>
> I see how this:
>
> toString ((34 :: Int), (44 :: Int))
>
> can match with the second and third instances, and thus the compiler has
> ambiguity on which instance to use.
Exactly, the type (Int,Int) matches (a,b) as well as (Int,Int) [and it also
matches (a,a), (Int,a), (a,Int)].
>
> Is there a way to express,
>
> Hey compiler, please use this instance:
>
> instance MyShow (Int, Int)
>
> That is, when confronted with overlapping instances, what should I do?
That is what OverlappingInstances does, iirc; when several instance heads
match, it chooses the most specific one if there is a well-defined most
specific instance. If there is no well-defined most specific one, a compile
error happens.
But it's somewhat delicate, if you have a function
foo :: (MyShow a) => a -> String
and at some place you call it with an (Int,Int) argument, it may be that
the compiler uses the general (a,b) instance and not the (Int,Int) one.
Generally, OverlappingInstances are considered dangerous and if possible
you should avoid them, and if you use them, you'd better know very well how
instance selection happens.
HTH,
Daniel
More information about the Beginners
mailing list