Am I missing something about unfoldr?
Carter Schonwald
carter.schonwald at gmail.com
Sat Jul 26 20:28:09 UTC 2014
its worth point out that many uses of fusion in haskell libs punt on
preserving bottoms, that is, fusion can make *more* programs terminate. I
don't have a good example off hand mind you
On Sat, Jul 26, 2014 at 4:02 PM, David Feuer <david.feuer at gmail.com> wrote:
> Hmm... I found something I missed. I need to prove that this doesn't break
> when the arguments to unfold use seq (if in fact it doesn't). I will have
> to look into it later.
> On Jul 26, 2014 3:34 PM, "David Feuer" <david.feuer at gmail.com> wrote:
>
>> The current definition:
>>
>> unfoldr :: (b -> Maybe (a, b)) -> b -> [a]
>> unfoldr f b = case f b of
>> Just (a,new_b) -> a : unfoldr f new_b
>> Nothing -> []
>>
>> I haven't yet looked over the Core to see if GHC is able to do a
>> worker/wrapper transformation to inline it, but we definitely want to
>> inline it (in some appropriate phase), because doing so has the potential
>> to erase the Maybes. It also isn't a good producer for foldr/build.
>> However, if we (re)write it like this:
>>
>> unfoldrB f b c n = go b
>> where
>> go b = case f b of
>> Just (a,new_b) -> a `c` go new_b
>> Nothing -> n
>>
>> unfoldr f b = build (unfoldrB f b)
>>
>> then we get some really nice fusion:
>>
>> foldr c n (unfoldr f b)
>> = foldr c n (build (unfoldrB f b))
>> = unfoldrB f b c n
>>
>> The list is gone, and there are no new closures or data structures in its
>> place.
>>
>> As a side benefit, we could write groupBy as an unfoldr, and make it a
>> somewhat better producer, especially when the groups are small. I don't
>> *think* there's any way to make groupBy a good consumer for foldr/build,
>> unfortunately.
>>
>
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