Data.HashMap: Strict or lazy by default?
ekmett at gmail.com
Sat Feb 19 00:21:47 CET 2011
On Fri, Feb 18, 2011 at 3:32 PM, Johan Tibell <johan.tibell at gmail.com>wrote:
> On Thu, Feb 17, 2011 at 4:51 PM, Johan Tibell <johan.tibell at gmail.com>
> > My current thinking is to provide lazy and strict versions in
> > different modules. The two modules could still share the same data
> > type. The question is, what should be the default? Haskell is a lazy
> > language but the most common use cases for maps are strict (e.g. a map
> > from strings to integer counters).
> What about class instances? With a shared data type we can only
> provide one set of instances, probably the lazy ones. Assuming we used
> to separate data types, can we even define instances for all common
> classes (e.g. Functor, Foldable, Monoid) or will the strict versions
> violate some of the laws for these classes?
Hrmm, the strict version will violate the laws for Functor:
(fmap (const 12) . fmap error) /= fmap (const 12 . error)
and strictness is irrelevant for Monoid and Foldable as the former would be
grafting trees that already contain forced values, and the Foldable instance
only evaluates hashmaps, it doesn't produce them.
Traversable doesn't have laws explicitly stated, but the fmapDefault it
generates would violate the Functor laws given a strict map, indicating
something isn't kosher with a strict traversable either.
So it would seem at first glance, no (valid) instances are affected for
Now, I have some more ad-hoc methods in my 'keys' package which might have
their behavior affected by the strict/lazy divide since I don't provide a
full suite of laws for them (they provide some generic insert, adjust, etc.
properties that i wanted for manipulating representable functors). But, if
you split the types, you probably still want to allow users to splash a bit
of laziness/strictness in turn, so it would seem you'd wind up with 2 types,
4 modules, and a lot of boilerplate. Ick.
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