#4189: Add (<.>) operator (generalizing (.) to Functor)

[Maciej Marcin Piechotka]

On 01/08/10 16:05, Felipe Lessa wrote:
> +1
> 
> What should be its fixity?
> 

I guess right:

\a b c -> a <.> b <.> c
  :: (Functor f) =>
     (a1 -> b) -> (a11 -> a1) -> (a -> f a11) -> a -> f b

As opposed to:

\a b c -> a <.> b <.> c
  :: (Functor f, Functor f1) =>
     (a1 -> b) -> (a11 -> f a1) -> (a -> f1 a11) -> a -> f1 (f b)

Regards

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