Time

[Graham Klyne]

Merely a datum, not a proof-of-correctness...

[[
    The grammar element time-second may have the value "60" at the end of
    months in which a leap second occurs -- to date: June (XXXX-06-
    30T23:59:60Z) or December (XXXX-12-31T23:59:60Z); see Appendix D for
    a table of leap seconds.  It is also possible for a leap second to be
    subtracted, at which times the maximum value of time-second is "58".
    At all other times the maximum value of time-second is "59".
    Further, in time zones other than "Z", the leap second point is
    shifted by the zone offset (so it happens at the same instant around
    the globe).
]]
-- http://www.ietf.org/rfc/rfc3339.txt

#g
--

At 09:46 27/01/05 +0000, Simon Marlow wrote:
>On 26 January 2005 21:27, Peter Simons wrote:
>
> > Marcin 'Qrczak' Kowalczyk writes:
> >
> >  >> 23:59:60
> >
> >  > [...] and UTC doesn't have leap seconds.
> >
> > Just a minor point ... it does, see above. ;-) I'm not sure
> > how the loss of a second would be expressed, though.
>
>This is quite a subtle point.  What people have been referring to as
>"UTC seconds" I would call time_t.  time_t does not include leap seconds
>in its count; rather the actual duration of a second gets longer around
>a leap second.
>
>UTC is a calendar in which some minutes have 61 seconds.
>
>My library in fact maps both seconds to 23:59:59 at a leap second:
>
> > let t = CalendarTime{ ctYear=1998, ctMonth=11, ctDay=31, ctHour=23,
>ctMin=59, ctSec=59, ctPicosec=0, ctTZ=utcTimezone }
> > clockTimeToUTCTime (fromJust (calendarTimeToClockTime t))
>Thu Dec 31 23:59:59 UTC 1998
> > clockTimeToUTCTime (fromJust (calendarTimeToClockTime t) + 10^12)
>Thu Dec 31 23:59:59 UTC 1998
> > clockTimeToUTCTime (fromJust (calendarTimeToClockTime t) + 2*10^12)
>Fri Jan  1 00:00:00 UTC 1999
>
>(adding 10^12 for a second because ClockTime is measured in
>picoseconds).
>
>Cheers,
>         Simon
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------------
Graham Klyne
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