Language.Haskell.Parser and layout rules
Ross Paterson
ross at soi.city.ac.uk
Tue Feb 22 06:23:26 EST 2005
On Tue, Feb 22, 2005 at 11:14:22AM +0000, Malcolm Wallace wrote:
> > > ** A:
> > > g xs = do ys <- workM xs
> > > if null ys then return [] else do
> > > zs <- workM ys
> > > return zs
>
> I believe nhc98 is correct in parsing this as:
>
> g xs = do ys <- workM xs (if null ys then return [] else do
> zs <- workM ys
> return zs)
I don't think so:
exp10 -> ...
| if exp then exp else exp
| fexp
fexp -> [fexp] aexp
The argument can't be an if-expression.
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