[jhc] Parsec with JHC

[Agent Zhang]

Hi, there

Is it possible to compile Haskell programs using Parsec using JHC? I'm
trying jhc  0.5.20080307 (the rpm downloaded from JHC's homepage) with
the Parsec source tarball downloaded from here:

   http://legacy.cs.uu.nl/daan/download/parsec/parsec-2.0.zip

I'm getting the following errors during compiling:

   $ jhc Main.hs -i ~/tmp/haskell/parsec -o test
   jhc: Syntax error in input, run through a compiler to check.
        ERROR: the precedence of HsVar {hsExpName =
Text.ParserCombinators.Parsec.Prim.<|>} is incompatible with the
precendence of it's argument: HsInfixApp (HsVar {hsExpName =
Text.ParserCombinators.Parsec.Combinator.146_op}) (HsVar {hsExpName =
Jhc.Monad.>>=}) (HsLambda
/home/agentz/tmp/haskell/parsec/Text/ParserCombinators/Parsec/Combinator.hs:109:41
[HsPVar {hsPatName = Text.ParserCombinators.Parsec.Combinator.149_f}]
(HsInfixApp (HsVar {hsExpName =
Text.ParserCombinators.Parsec.Combinator.145_p}) (HsVar {hsExpName =
Jhc.Monad.>>=}) (HsLambda
/home/agentz/tmp/haskell/parsec/Text/ParserCombinators/Parsec/Combinator.hs:110:41
[HsPVar {hsPatName = Text.ParserCombinators.Parsec.Combinator.150_y}]
(HsApp (HsVar {hsExpName =
Text.ParserCombinators.Parsec.Combinator.147_rest}) (HsParen (HsApp
(HsApp (HsVar {hsExpName =
Text.ParserCombinators.Parsec.Combinator.149_f}) (HsVar {hsExpName =
Text.ParserCombinators.Parsec.Combinator.148_x})) (HsVar {hsExpName =
Text.ParserCombinators.Parsec.Combinator.150_y})))))))

Can I work around with it? Thanks in advance :)

Cheers,
-agentzh