lennart at augustsson.net
Tue Dec 4 03:19:23 EST 2007
Good question. That must be a matter of taste, because as you say the read
will always produce the same result. But it sill is a bit of a strange
On Dec 4, 2007 6:25 AM, Conal Elliott <conal at conal.net> wrote:
> Oh. Simple enough. Thanks.
> Another question: why the IO in readIVar :: IVar a -> IO a, instead of
> just readIVar :: IVar a -> a? After all, won't readIVar iv yield the same
> result (eventually) every time it's called?
> On Dec 3, 2007 12:29 AM, Lennart Augustsson <lennart at augustsson.net>
> > You can make them from MVars.
> > On Dec 2, 2007 8:03 PM, Conal Elliott <conal at conal.net> wrote:
> > > what became of (assign-once) IVars? afaict, they were in concurrent
> > > haskell and now aren't.
> > >
> > > _______________________________________________
> > > Haskell mailing list
> > > Haskell at haskell.org
> > > http://www.haskell.org/mailman/listinfo/haskell
> > >
> > >
> Haskell mailing list
> Haskell at haskell.org
-------------- next part --------------
An HTML attachment was scrubbed...
More information about the Haskell