[Haskell] GHC inferred type different for pointed/point-free defs?

[Dan Weston]

Help! One of two things is going on:

1) I don't understand what I'm doing
2) GHC is inferring different types for pointed and
    point-free function definition.

I wanted to define Haskell equivalents to the C ternary operator.
Basically, predicate ??? doIfTrue ||| doIfFalse

For some reason, though, in GHC 6.4 and 6.7, the types
inferred for abs1 and ab2 (defined below) are different:

*Main> :t abs1
abs1 :: (Num a, Ord a) => a -> a

*Main> :t abs2
abs2 :: Integer -> Integer

How is abs2 less general just because I use point-free
notation instead of pointed notation? They should have the same
type, no?  I'm stumped...

 > import Control.Arrow
 > import Data.Either
 >
 > infix 1 ?, ??, ???, ????
 >
 > (?)  True  = Left
 > (?)  False = Right
 >
 > (??) True  = Left  . fst
 > (??) False = Right . snd
 >
 > p ???  q = (p &&& arr id) >>> uncurry (?)  >>> q
 > p ???? q = (p &&& arr id) >>> uncurry (??) >>> q
 >
 > abs1 x = (< 0) ??? negate ||| id $ x
 > abs2   = (< 0) ??? negate ||| id
 >
 > checks :: [Bool]
 > checks =
 >  [
 >   (True   ?                              3 ) == (Left   3),
 >   (False  ?                              4 ) == (Right  4),
 >   (True  ??                           (3,4)) == (Left   3),
 >   (False ??                           (3,4)) == (Right  4),
 >   (even ??? (`div` 2) ||| (+1).(*3) $  3   ) == (      10),
 >   (even ??? (`div` 2) ||| (+1).(*3) $    4 ) == (       2),
 >   (uncurry (==) ????  (+1) ||| (*3) $ (3,3)) == (       4),
 >   (uncurry (==) ????  (+1) ||| (*3) $ (3,4)) == (      12),
 >   (uncurry (==) ????  (+1) +++ (*3) $ (3,3)) == (Left   4),
 >   (uncurry (==) ????  (+1) +++ (*3) $ (3,4)) == (Right 12),
 >   (abs1   5                                ) == (       5),
 >   (abs1 (-5)                               ) == (       5),
 >   (abs2   5                                ) == (       5),
 >   (abs2 (-5)                               ) == (       5)
 >  ]
 >
 > main = print (and checks)