[Haskell] instance Bounded Double

[Lennart Augustsson]

Haskell does not guarantee that 1/0 is well defined,
nor that -(1/0) is different from 1/0.
While the former is true for IEEE floating point numbers,
the latter is only true when using affine infinities.

	-- Lennart

Frederik Eaton wrote:
> Shouldn't Double, Float, etc. be instances of Bounded?
> 
> I've declared e.g.
> 
> instance Bounded Double where
>     minBound = -(1/0)
>     maxBound = 1/0
> 
> in a module where I needed it and there doesn't seem to be any issue
> with the definition...
> 
> Frederik
>