[Haskell] Running haskell from within Haskell
vivian.mcphail at paradise.net.nz
Tue Jan 18 21:39:11 EST 2005
I have a parser which has entries for each word, such as:
ate = s \ np / np : ^x y.did(eat y x);
so each word has a type (s \ np / np) and a semantics (the lambda term ^x y.did(eat y x)).
Currently I parse the semantics into lambda terms and use my own lambda-interpreter to do evaluation.
"I ate a python programmer" would be evaluated as:
did(eat I (a python programmer))
What I would like to be able to do is actually use haskell functions in the semantic slot for each word. This requires parsing a fragment of a file into haskell and then making it available as code within my program.
Is this possible?
kicked = s \ np / np : \x y -> case x of
(the bucket) = did(die y)
_ = did(kick y x);
Thanks in advance.
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