[Haskell] Why is newChan in the IO Monad?

[S. Alexander Jacobson]

Nothing actually happens when newChan is called
except construction of a new datastructure.  It
would be nice to have non IO monad code be able to
create a new Chan that gets passed to IO code that
uses it somewhere else.

Alternatively, is there a way to create a Chan
outside the IO monad?

-Alex-

_________________________________________________________________
S. Alexander Jacobson                  mailto:me at alexjacobson.com
tel:917-770-6565                       http://alexjacobson.com